231 Cu. in / 1728 = 0.1337 cu ft

X 4000 RPMs = 534.72 CFM........

Alot of air.............

I really need to find my sciance book to see if it has the conversions so I can figure out the flow rate for a 120CU ft tank at 3500psi or 120Cu Ft. at 238.095 atm

1 atm = 14.7 psi
3500psi / 14.7 = 238.095 atm

So the engine at 4000rpm uses 534.72 CFM being pulled from ~1ATM and the tank being reduced to 1atm would be 120cu ft x 238.095 = 28571.4cu ft at 1 atm
28571.4 / 534.72CFM = 53.43 so if the valve would allow the tank to flow there it would beable to support the engine for ~53.5min @ 4000RPMs

So I think if a NA engine was pulling 534CFM and I add pressurised air to the intake it would add some boost or some what of a Ram air affect

this pure O2 or just regular compressed air?

In order to pressurize the intake, you would need to first make up all of the required CFM and then you would see an increase in boost. IMHO, I wouldn't add pressure to an already weak plastic intake.

if its pure O2 then it might make a difference.

I've never seen that calculation before, what is the '1738' number?
The calculation I've seen is RPM x displacement / 3456. That'd make it 401cfm at 6000rpm. Thats also assuming a 'doesn't have it' 100% VE.

1728 cu in = 1 cu ft

Oh well in that case you just forgot to divide by two (only pulls air every other 'rotation').

DJ... Right you are ... my mistake.... Still too much to do what he'* suggesting... Just add the turbo and be done with it