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-   Performance, Brainstorming & Tuning (https://www.gmforum.com/performance-brainstorming-tuning-96/)
-   -   Dyno results (https://www.gmforum.com/performance-brainstorming-tuning-96/dyno-results-213414/)

J Wikoff 02-28-2005 08:37 AM

How do dynos measure RPM? Do they clamp onto a spark plug wire and use induction? If so, our spark plugs fire every revolution. I don't actually know if most newer cars are that way, but I dont' think it's uncommon. Maybe it doesn't take that into account.

toastedoats 02-28-2005 09:14 AM

they did induction off of #1 wire

banned3800 02-28-2005 10:18 AM

I'd say multiply that torque number by 2 then... 91 is just tooo whimpy... 182Ft Lbs sounds a bit better....


Does that sound right for the drivetrain loss... 230ft lbs to 182 ft lbs ?

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BonneMeMN 02-28-2005 10:39 AM

Re: Dyno results
 

Originally Posted by toastedoats
145.06whp @ 4200
91.62wtq @ 4100

Doesnt that seem a little screwy?

It's still wrong. HP = ( Torque x RPM)/5250 Lets use the first figure...

145.06 HP = (116.048 ft/lb X 4200) / 5250

116lb/ft is higher the 91.62 as well, and there's no way your car is making peak torque above 4200 RPM either. This figure seems low for low RPMs even if we start dividing and such :roll:

dbtk2 02-28-2005 10:40 AM

Well, it is quite obvious the rpm isn't right since peak power and peak torque come at pretty much the same exact time, and its way too low for peak hp. (4100 and 4200) The hp number seems right, but the rpms don't. Do you have the chart? If hp & tq. don't cross at 5252rpm then there is obviously something wrong. If the rpm is off, the hp should still be the same the torque will just read different. I would bet you have to double the torque numbers.


there is no way that a 3.8 with IC, heads and a cam only makes 312hp
Someones never been on ClubGP apparantly. There are many people with cam/heads/IC only making 312whp. Thats 390 crank hp. I'm not saying those numbers are right, because they probably aren't. But without tuning its pretty easy to not make a lot of power. For instance, take a look at this clubgp post. Its the hp records for each cam, go down and look at the Stage 2 cam, the second person on there. Yeah, I understand this is a smaller cam, but as an example. Stage 2 cam/heads/IC. And I'm pretty sure this was a well tuned car as well. So a little tuning on this car that only made 312 that we are talking about might have helped it. Or the dyno was off, you never know.

http://www.clubgp.com/newforum/tm.as...mode=1&smode=1

Shawn

fantastic88 02-28-2005 11:02 AM


If so, our spark plugs fire every revolution.
Yes, thats the reason they gave me that it said I was turning 12,000 RPM. Just double you're torque numbers.

fantastic88 02-28-2005 11:23 AM

http://tinypic.com/1h9t1k

Heres mine. Notice the RPMs are doubled?

J Wikoff 02-28-2005 11:29 AM

Re: Dyno results
 

Originally Posted by BonneMeMN

Originally Posted by toastedoats
145.06whp @ 4200
91.62wtq @ 4100

Doesnt that seem a little screwy?

It's still wrong. HP = ( Torque x RPM)/5250 Lets use the first figure...

145.06 HP = (116.048 ft/lb X 4200) / 5250

116lb/ft is higher the 91.62 as well, and there's no way your car is making peak torque above 4200 RPM either. This figure seems low for low RPMs even if we start dividing and such :roll:

145.06 HP = (181.325 ft/lb X 4200) / 5250

That sounds a lot better. ;)

BonneMeMN 02-28-2005 12:25 PM

Re: Dyno results
 

Originally Posted by jwikoff99

low for low RPMs even if we start dividing and such :roll:
145.06 HP = (181.325 ft/lb X 4200) / 5250

That sounds a lot better. ;)

Oye, that's what I get for using the damn computer calculator instead of the Trusty Ti, or a paper... :roll:

Dumb question, it's a 4 stroke motor, so it takes two revolutions to doa full cycle, why is the spark plug firing every rev? Because of the matching cylinder on the ignition coil?

banned3800 02-28-2005 12:30 PM

Something like that... GM DIS uses a waste spark method... The coil actually fires both plugs at the same time... The cylinder on the compression stroke requires more power to fire the plug, the opposing cylinder requires a lot less power to fire the plug, hence sending more of the power to the plug on the compression stroke...

Did I even explain that right :roll:

It works something like that....<---- To lazy to look it up...lol

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