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Old 04-04-2007, 06:21 AM   #1
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Default I.C.P.E. question

Okay we all know how the 4 cycle engine works where you have Intake-Compression-Power-Exhaust. . .

My question is when #1 cylinder'* piston is on the compression stroke approaching top dead center, are any of the other pistons in the exact same position on the compression stroke?
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Old 04-04-2007, 07:21 AM   #2
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Exact position, probably not. On the compression stroke..yes.
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Old 04-04-2007, 08:18 AM   #3
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Alright then which of the other cylinders are at TDC compression at the same time as #1?

I'm talking about the 3800 of course.
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Old 04-04-2007, 09:21 AM   #4
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None of them. The opposite cylinder on that ignition coil is TDC on the Exhaust stroke at the same time. Firing order is literally in numeric order.
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Old 04-04-2007, 07:42 PM   #5
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Okay, that would mean that the remaining 4 cylinders are at various positions of crankshaft rotation between TDC compression and TDC exhaust then correct?
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Old 04-04-2007, 07:45 PM   #6
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Quote:
Originally Posted by MACDRIVE
Okay, that would mean that the remaining 4 cylinders are at various positions of crankshaft rotation between TDC compression and TDC exhaust then correct?
Here'* a crankshaft for ya
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Old 04-04-2007, 08:06 PM   #7
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Okay, going by what WillWren said, #1 is at TDC Compression while #4 is at TDC Exhaust; I'm just wondering what position the other four cylinders are at during that time.

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Old 04-06-2007, 09:36 PM   #8
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The piston lobes have 60 degree seperation, if that helps.
ie 1 & 6 make a 60 degree angle
6 & 5 make another 60 degree angle (1&5 make a 120)
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