MSD vs Series II L67 coils
11-12-2005, 05:15 PM
#11
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Originally Posted by llBlazin_llLo
That is what I'm saying Rogue. Also Rogue (not to get off topic) but is that one of the things that was changed to the turbo car to get that 9 sec. slip? What coils is the turbo car running now? I know I heard SC saying that Intense was working a few things out and I thought I heard that Rob was helping out with the tune but what was actually changed to gain .2 and 5 mph?
We are running a DIS 4 ignition system on the Turbo Car with MSD coils.
11-12-2005, 09:44 PM
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Originally Posted by J Wikoff
I'll get the multimeter out of the trunk later and ohm the Series I set I have here.
Originally Posted by Rogue
Once we got a trans that could hold we just turned up the boost. Unfortunately the GM turbine shaft (Rated at 1200hp) is no longer holding at the current boost level. We have broken two in the past month and are currently the only car to do so.
We are running a DIS 4 ignition system on the Turbo Car with MSD coils.
We are running a DIS 4 ignition system on the Turbo Car with MSD coils.
What was the boost set to on that run? As heavy as a w-body is and the torque that car makes it doesn't surprise me. 
(not to even to mention how hard you launch)
11-12-2005, 10:25 PM
#13
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Series I coils: 5.7k secondary and .9 primary
Oh, I have a set of Accel coils somewhere at my parents' place. I try to remember to dig the out tomorrow and test them, too. Not gonna put them on though... they had this little issue of a horrendous occasional backfire or something that would cause a high rpm pop and immediate 3k RPM drop. Scared me, so I took them off, they might be good for a NA engine, but I'm not gonna try them on anything.
Oh, I have a set of Accel coils somewhere at my parents' place. I try to remember to dig the out tomorrow and test them, too. Not gonna put them on though... they had this little issue of a horrendous occasional backfire or something that would cause a high rpm pop and immediate 3k RPM drop. Scared me, so I took them off, they might be good for a NA engine, but I'm not gonna try them on anything.
11-13-2005, 10:04 PM
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Originally Posted by Rogue
Stock ignition system for a series II is good up to at least 700 crank hp. We still run stock coils on our 10sec Bonnie as well as every other car in our stable except the turbo car. Unless your having problems with your current system and need to replace all your coils or ignition system money may be better spent on other things.
11-13-2005, 11:20 PM
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Originally Posted by willwren
Originally Posted by Rogue
Stock ignition system for a series II is good up to at least 700 crank hp. We still run stock coils on our 10sec Bonnie as well as every other car in our stable except the turbo car. Unless your having problems with your current system and need to replace all your coils or ignition system money may be better spent on other things.
11-13-2005, 11:53 PM
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Re: MSD vs Series II L67 coils
Originally Posted by willwren
Because the 92-96 SSEi coils and the 92-current production NA coils are weaker than the 97+ SC coils, most cars, particularly the 92-95 L67'* with benefit from a smoother idle and slightly improved mid-range power after switching to MSD'*.
Originally Posted by J Wikoff
I just compared a MSD coil to a Series II L67 coil.
MSD:
Primary .8 Secondary 6k
Series II
Primary .9 Secondary 5.78k
I believe the greater the resistance difference, the greater the output voltage.
Advantage: MSD
MSD:
Primary .8 Secondary 6k
Series II
Primary .9 Secondary 5.78k
Originally Posted by J Wikoff
Series I coils: 5.7k secondary and .9 primary
Advantage: MSD
11-14-2005, 12:53 PM
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If you want to know the difference in current between them the formula you use would be
V
i | R
P
i | v
(You just cover the letter you are trying to find to get it V= I * R
V = voltage
I = Amps (current)
R = resistance
P = Wats (power)
IIRC the voltage would stay the same but increasing the resistance from 5.78 to 6 would change the current from say 17.3A to 16.6A
V
i | R
P
i | v
(You just cover the letter you are trying to find to get it V= I * R
V = voltage
I = Amps (current)
R = resistance
P = Wats (power)
IIRC the voltage would stay the same but increasing the resistance from 5.78 to 6 would change the current from say 17.3A to 16.6A
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