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Old Sep 24, 2003 | 10:21 AM
  #11  
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Originally Posted by LS1'edSSE
Its not really that hard to figure out.To put it in simple terms. Actually I cant.( i just looked at it & knew( MAth wiz but dont ask me to explain).
The red triangle is 1 bolck higher than the green& longer than the green. So when you swap them you need to move the yellow one down, to compensate. Obvously you will have one space( you put 3 blocks over 2 you will obviously have one space.
Dont think to hard.
That'* what I thought too, but it doesn't quite do it...the problem is you have 4 objects that when put together one way have one surface area and when put together another way, have less...wtf???
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Old Sep 24, 2003 | 11:42 AM
  #12  
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Also, if you notice, by switching it around, the hypotenuse of the angle is slightly bigger. Take the total distance of it, bundle it, and you have one square of space!!
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Old Sep 24, 2003 | 11:56 AM
  #13  
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Its very simple. Stop thinking so hard. Look at the L shaped piece with 7 blocks. If you move that down you need to move it over 3 bolcks. That leaves you with an open space, plan & simple. It also makes up for the distance that was lost with the big triangle. Big triangle on top, move the small one out front. Boom done. I really dont see why this is so hard.
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Old Sep 24, 2003 | 12:04 PM
  #14  
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It'* not a true triangle. 2/5 is not equal to 3/8.
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Old Sep 24, 2003 | 06:57 PM
  #15  
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teh hypotenuse is the same b\c the legs are the same, you dont really lose any area when you think about it, you are just rearranging the same thing. I dont get whats so hard aobut it...
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Old Sep 24, 2003 | 07:39 PM
  #16  
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The pieces still take up the same amount of space, but once you arrange it differently you're left with that open block. Just depends how it'* arranged. It'* meant to look harder than it really is.
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Old Sep 24, 2003 | 08:53 PM
  #17  
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Default triangle or no triangle?

i think the dude above my post is correct for this lil puzzle. it is meant to look harder than it is. its all in the arrangement to get the empty space. all the pieces are the same size in both diagrams(as it was stated). i think Akhams Razor is in effect here. take care all

Urban Cowboy
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Old Sep 24, 2003 | 08:56 PM
  #18  
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Yes Marco..lol

Akhams Razor, the simplest answer is usually the right one
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Old Sep 24, 2003 | 08:59 PM
  #19  
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I HATE MATH!!!!!!!!!!!!!!!!!!!!!!!!
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Old Sep 25, 2003 | 07:56 AM
  #20  
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Originally Posted by macho_mike21
teh hypotenuse is the same b\c the legs are the same, you dont really lose any area when you think about it, you are just rearranging the same thing. I dont get whats so hard aobut it...
Heheh!! Yes, the hypotenuse is the same. I was *kidding*!!
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