Math Help
09-13-2006, 12:07 AM
#12
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Originally Posted by Technical Ted
1,921*417=801,057
09-13-2006, 12:13 AM
#13
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I see it now.
4th digit has to be 1
?057
-417
=040
3rd digit has to be 2 to get the 4
21x417=8757
??057
-8757
=300
2nd digit has to be 9 to get the 3
4th digit has to be 1
?057
-417
=040
3rd digit has to be 2 to get the 4
21x417=8757
??057
-8757
=300
2nd digit has to be 9 to get the 3
09-13-2006, 07:48 AM
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The answer is 42!! Don't you people know anything????
I probably would have taken the pass on the original equation. That'* why I'm such a success now....
I probably would have taken the pass on the original equation. That'* why I'm such a success now....
09-13-2006, 10:05 AM
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jeez I'll trade you math problems any day....
one from my most recent HW...
verify each given function is a solution of the equation
y''''+4y'''+3y=t where y1(t)= (t/3) and y2(t)= e^(-t) + (t/3)
dont worry though, I already turned the hw in so you dont have to solve it
one from my most recent HW...
verify each given function is a solution of the equation
y''''+4y'''+3y=t where y1(t)= (t/3) and y2(t)= e^(-t) + (t/3)
dont worry though, I already turned the hw in so you dont have to solve it
09-13-2006, 10:48 AM
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Originally Posted by corvettecrazy
jeez I'll trade you math problems any day....
one from my most recent HW...
verify each given function is a solution of the equation
y''''+4y'''+3y=t where y1(t)= (t/3) and y2(t)= e^(-t) + (t/3)
dont worry though, I already turned the hw in so you dont have to solve it
one from my most recent HW...
verify each given function is a solution of the equation
y''''+4y'''+3y=t where y1(t)= (t/3) and y2(t)= e^(-t) + (t/3)
dont worry though, I already turned the hw in so you dont have to solve it