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Calculus freaks...I need help!

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Old 09-24-2006, 06:01 PM
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Default Calculus freaks...I need help!

Alright so I'm doing some Calc II homework and I'm stuck on these two problems. I really don't have any idea where to even begin. Assume that ][ means integral. They are..

1) ][ e^2x cos e^2x dx =

and

3) ][ x^2 / (1 + x^6) dx=

I'd really appreciate any help guys!
Old 09-24-2006, 06:26 PM
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Flux capacitor :?:
Old 09-24-2006, 06:28 PM
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that Calc 2?
Old 09-24-2006, 06:40 PM
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Originally Posted by petraman
that Calc 2?
Originally Posted by VigCS
Alright so I'm doing some Calc II homework
Old 09-24-2006, 06:59 PM
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oop, missed that, yeah, I'm in Calc 1, sorry bud
Old 09-24-2006, 10:26 PM
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1 (1/2)sin(e^2x) +c

3 (tan^-1 (x^3))/3 +c
Old 09-24-2006, 10:28 PM
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Originally Posted by corvettecrazy
1 (1/2)sin(e^2x) +c

3 (tan^-1 (x^3))/3 +c
on the first one, let u = e^(2x), so du = 2e^(2x)
Old 09-24-2006, 10:31 PM
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Originally Posted by jwakamud
Originally Posted by corvettecrazy
1 (1/2)sin(e^2x) +c

3 (tan^-1 (x^3))/3 +c
on the first one, let u = e^(2x), so du = 2e^(2x)
that would work also.
Old 09-24-2006, 10:32 PM
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Originally Posted by jwakamud
Originally Posted by corvettecrazy
1 (1/2)sin(e^2x) +c

3 (tan^-1 (x^3))/3 +c
on the first one, let u = e^(2x), so du = 2e^(2x)
Chain rule!
Old 09-24-2006, 10:35 PM
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Originally Posted by 1995BvSSE
Originally Posted by jwakamud
Originally Posted by corvettecrazy
1 (1/2)sin(e^2x) +c

3 (tan^-1 (x^3))/3 +c
on the first one, let u = e^(2x), so du = 2e^(2x)
Chain rule!
or "U subsitution"


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